btrfs: use rb_entry() instead of container_of

To make the code clearer, use rb_entry() instead of container_of() to
deal with rbtree.

Signed-off-by: Geliang Tang <geliangtang@gmail.com>
Reviewed-by: Josef Bacik <jbacik@fb.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Geliang Tang 2016-12-19 22:53:41 +08:00 committed by David Sterba
parent f74670f713
commit 6b4df8b6c5

View File

@ -426,7 +426,7 @@ void btrfs_put_tree_mod_seq(struct btrfs_fs_info *fs_info,
tm_root = &fs_info->tree_mod_log;
for (node = rb_first(tm_root); node; node = next) {
next = rb_next(node);
tm = container_of(node, struct tree_mod_elem, node);
tm = rb_entry(node, struct tree_mod_elem, node);
if (tm->seq > min_seq)
continue;
rb_erase(node, tm_root);
@ -460,7 +460,7 @@ __tree_mod_log_insert(struct btrfs_fs_info *fs_info, struct tree_mod_elem *tm)
tm_root = &fs_info->tree_mod_log;
new = &tm_root->rb_node;
while (*new) {
cur = container_of(*new, struct tree_mod_elem, node);
cur = rb_entry(*new, struct tree_mod_elem, node);
parent = *new;
if (cur->logical < tm->logical)
new = &((*new)->rb_left);
@ -746,7 +746,7 @@ __tree_mod_log_search(struct btrfs_fs_info *fs_info, u64 start, u64 min_seq,
tm_root = &fs_info->tree_mod_log;
node = tm_root->rb_node;
while (node) {
cur = container_of(node, struct tree_mod_elem, node);
cur = rb_entry(node, struct tree_mod_elem, node);
if (cur->logical < start) {
node = node->rb_left;
} else if (cur->logical > start) {
@ -1326,7 +1326,7 @@ __tree_mod_log_rewind(struct btrfs_fs_info *fs_info, struct extent_buffer *eb,
next = rb_next(&tm->node);
if (!next)
break;
tm = container_of(next, struct tree_mod_elem, node);
tm = rb_entry(next, struct tree_mod_elem, node);
if (tm->logical != first_tm->logical)
break;
}