regmap: Do not call regcache_exit from regcache_rbtree_init error path
Calling regcache_exit from regcache_rbtree_init is first of all a layering violation and secondly will cause double frees. regcache_exit will free buffers allocated by the core, but the core will also free the same buffers when the cacheops init callback returns an error. Thus we end up with a double free. Fix this by not calling regcache_exit but only free those buffers which, have been allocated in this function. Signed-off-by: Lars-Peter Clausen <lars@metafoo.de> Acked-by: Dimitris Papastamos <dp@opensource.wolfsonmicro.com> Signed-off-by: Mark Brown <broonie@opensource.wolfsonmicro.com>
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				| @ -17,6 +17,7 @@ | ||||
| 
 | ||||
| static int regcache_rbtree_write(struct regmap *map, unsigned int reg, | ||||
| 				 unsigned int value); | ||||
| static int regcache_rbtree_exit(struct regmap *map); | ||||
| 
 | ||||
| struct regcache_rbtree_node { | ||||
| 	/* the actual rbtree node holding this block */ | ||||
| @ -149,7 +150,7 @@ static int regcache_rbtree_init(struct regmap *map) | ||||
| 	return 0; | ||||
| 
 | ||||
| err: | ||||
| 	regcache_exit(map); | ||||
| 	regcache_rbtree_exit(map); | ||||
| 	return ret; | ||||
| } | ||||
| 
 | ||||
|  | ||||
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