d1710561b0
'A || (!A && B)' is equivalent to 'A || B'. Let's reduce the complexity of the statement in start_jr0(). The problem was indicated by cppcheck. Signed-off-by: Heinrich Schuchardt <xypron.glpk@gmx.de> Reviewed-by: York Sun <york.sun@nxp.com> Reviewed-by: Simon Glass <sjg@chromium.org> |
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fsl | ||
rsa_mod_exp | ||
ace_sha.c | ||
ace_sha.h | ||
Kconfig | ||
Makefile |