dtoc: Adjust Node to record its parent
We need to be able to search back up the tree for #address-cells and #size-cells. Record the parent of each node to make this easier. Signed-off-by: Simon Glass <sjg@chromium.org> Reviewed-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com> Tested-by: Philipp Tomsich <philipp.tomsich@theobroma-systems.com> Tested-by: Kever Yang <kever.yang@rock-chips.com>
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@ -174,8 +174,9 @@ class Node:
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props: A dict of properties for this node, each a Prop object.
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Keyed by property name
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"""
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def __init__(self, fdt, offset, name, path):
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def __init__(self, fdt, parent, offset, name, path):
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self._fdt = fdt
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self.parent = parent
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self._offset = offset
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self.name = name
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self.path = path
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@ -217,7 +218,7 @@ class Node:
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sep = '' if self.path[-1] == '/' else '/'
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name = self._fdt._fdt_obj.get_name(offset)
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path = self.path + sep + name
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node = Node(self._fdt, offset, name, path)
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node = Node(self._fdt, self, offset, name, path)
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self.subnodes.append(node)
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node.Scan()
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@ -279,7 +280,7 @@ class Fdt:
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TODO(sjg@chromium.org): Implement the 'root' parameter
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"""
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self._root = self.Node(self, 0, '/', '/')
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self._root = self.Node(self, None, 0, '/', '/')
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self._root.Scan()
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def GetRoot(self):
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@ -386,7 +387,7 @@ class Fdt:
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return libfdt.fdt_off_dt_struct(self._fdt) + offset
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@classmethod
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def Node(self, fdt, offset, name, path):
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def Node(self, fdt, parent, offset, name, path):
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"""Create a new node
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This is used by Fdt.Scan() to create a new node using the correct
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@ -394,11 +395,12 @@ class Fdt:
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Args:
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fdt: Fdt object
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parent: Parent node, or None if this is the root node
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offset: Offset of node
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name: Node name
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path: Full path to node
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"""
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node = Node(fdt, offset, name, path)
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node = Node(fdt, parent, offset, name, path)
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return node
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def FdtScan(fname):
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