x86: Allow I/O functions to use pointers
It is common with memory-mapped I/O to use the address of a structure member to access memory, as in: struct some_regs { u32 ctrl; u32 data; } struct some_regs *regs = (struct some_regs *)BASE_ADDRESS; writel(1, ®->ctrl); writel(2, ®->data); This does not currently work with inl(), outl(), etc. Add a cast to permit this. Signed-off-by: Simon Glass <sjg@chromium.org> Reviewed-by: Bin Meng <bmeng.cn@gmail.com>
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@ -202,7 +202,7 @@ out:
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* Talk about misusing macros..
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*/
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#define __OUT1(s,x) \
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static inline void out##s(unsigned x value, unsigned short port) {
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static inline void _out##s(unsigned x value, unsigned short port) {
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#define __OUT2(s,s1,s2) \
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__asm__ __volatile__ ("out" #s " %" s1 "0,%" s2 "1"
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@ -213,7 +213,7 @@ __OUT1(s,x) __OUT2(s,s1,"w") : : "a" (value), "Nd" (port)); } \
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__OUT1(s##_p,x) __OUT2(s,s1,"w") __FULL_SLOW_DOWN_IO : : "a" (value), "Nd" (port));}
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#define __IN1(s) \
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static inline RETURN_TYPE in##s(unsigned short port) { RETURN_TYPE _v;
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static inline RETURN_TYPE _in##s(unsigned short port) { RETURN_TYPE _v;
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#define __IN2(s,s1,s2) \
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__asm__ __volatile__ ("in" #s " %" s2 "1,%" s1 "0"
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@ -242,10 +242,18 @@ __IN(w,"")
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__IN(l,"")
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#undef RETURN_TYPE
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#define inb(port) _inb((uintptr_t)(port))
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#define inw(port) _inw((uintptr_t)(port))
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#define inl(port) _inl((uintptr_t)(port))
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__OUT(b,"b",char)
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__OUT(w,"w",short)
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__OUT(l,,int)
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#define outb(val, port) _outb(val, (uintptr_t)(port))
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#define outw(val, port) _outw(val, (uintptr_t)(port))
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#define outl(val, port) _outl(val, (uintptr_t)(port))
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__INS(b)
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__INS(w)
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__INS(l)
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