Test whether unprivileged would be able to leak the spilled pointer either
by exporting the returned value from the atomic{32,64} operation or by reading
and exporting the value from the stack after the atomic operation took place.
Note that for unprivileged, the below atomic cmpxchg test case named "Dest
pointer in r0 - succeed" is failing. The reason is that in the dst memory
location (r10 -8) there is the spilled register r10:
0: R1=ctx(id=0,off=0,imm=0) R10=fp0
0: (bf) r0 = r10
1: R0_w=fp0 R1=ctx(id=0,off=0,imm=0) R10=fp0
1: (7b) *(u64 *)(r10 -8) = r0
2: R0_w=fp0 R1=ctx(id=0,off=0,imm=0) R10=fp0 fp-8_w=fp
2: (b7) r1 = 0
3: R0_w=fp0 R1_w=invP0 R10=fp0 fp-8_w=fp
3: (db) r0 = atomic64_cmpxchg((u64 *)(r10 -8), r0, r1)
4: R0_w=fp0 R1_w=invP0 R10=fp0 fp-8_w=mmmmmmmm
4: (79) r1 = *(u64 *)(r0 -8)
5: R0_w=fp0 R1_w=invP(id=0) R10=fp0 fp-8_w=mmmmmmmm
5: (b7) r0 = 0
6: R0_w=invP0 R1_w=invP(id=0) R10=fp0 fp-8_w=mmmmmmmm
6: (95) exit
However, allowing this case for unprivileged is a bit useless given an
update with a new pointer will fail anyway:
0: R1=ctx(id=0,off=0,imm=0) R10=fp0
0: (bf) r0 = r10
1: R0_w=fp0 R1=ctx(id=0,off=0,imm=0) R10=fp0
1: (7b) *(u64 *)(r10 -8) = r0
2: R0_w=fp0 R1=ctx(id=0,off=0,imm=0) R10=fp0 fp-8_w=fp
2: (db) r0 = atomic64_cmpxchg((u64 *)(r10 -8), r0, r10)
R10 leaks addr into mem
Acked-by: Brendan Jackman <jackmanb@google.com>
Signed-off-by: Daniel Borkmann <daniel@iogearbox.net>
Signed-off-by: Alexei Starovoitov <ast@kernel.org>
180486b430