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regmap: pass buffer size to regmap_raw_read() in regcache_hw_init()

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regcache_hw_init() uses regmap_raw_read() to initialize cache
when reg_defaults_raw isn't provided.

The last parameter to regmap_raw_read() is buffer size in bytes,
however regcache_hw_init() called it with number of registers
to read instead, which cause problem if they aren't one byte
wide in cache.

This wasn't triggered by any of current in-tree drivers
since they either have one-byte registers or provide
reg_defaults_raw explicitly.

Signed-off-by: Maciej S. Szmigiero <mail@maciej.szmigiero.name>
Signed-off-by: Mark Brown <broonie@kernel.org>
This commit is contained in:
Maciej S. Szmigiero 2016-01-13 22:41:12 +01:00 committed by Mark Brown
parent 8005c49d9a
commit d51fe1f393
1 changed files with 2 additions and 2 deletions
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4
drivers/base/regmap/regcache.c
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@ -57,7 +57,7 @@ static int regcache_hw_init(struct regmap *map)
bool cache_bypass = map->cache_bypass;
dev_warn(map->dev, "No cache defaults, reading back from HW\n");
/* Bypass the cache access till data read from HW*/
/* Bypass the cache access till data read from HW */
map->cache_bypass = true;
tmp_buf = kmalloc(map->cache_size_raw, GFP_KERNEL);
if (!tmp_buf) {
@ -65,7 +65,7 @@ static int regcache_hw_init(struct regmap *map)
goto err_free;
}
ret = regmap_raw_read(map, 0, tmp_buf,
map->num_reg_defaults_raw);
map->cache_size_raw);
map->cache_bypass = cache_bypass;
if (ret < 0)
goto err_cache_free;