forked from Minki/linux
pinctrl: rza1: Add of_node_put() before return
Each iteration of for_each_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return in three places. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com> Signed-off-by: Geert Uytterhoeven <geert+renesas@glider.be>
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@ -866,8 +866,10 @@ static int rza1_dt_node_pin_count(struct device_node *np)
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npins = 0;
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for_each_child_of_node(np, child) {
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of_pins = of_find_property(child, "pinmux", NULL);
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if (!of_pins)
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if (!of_pins) {
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of_node_put(child);
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return -EINVAL;
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}
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npins += of_pins->length / sizeof(u32);
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}
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@ -1025,8 +1027,10 @@ static int rza1_dt_node_to_map(struct pinctrl_dev *pctldev,
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for_each_child_of_node(np, child) {
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ret = rza1_parse_pinmux_node(rza1_pctl, child, mux_conf,
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grpin);
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if (ret < 0)
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if (ret < 0) {
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of_node_put(child);
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return ret;
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}
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grpin += ret;
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mux_conf += ret;
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@ -1272,8 +1276,10 @@ static int rza1_gpio_register(struct rza1_pinctrl *rza1_pctl)
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ret = rza1_parse_gpiochip(rza1_pctl, child, &gpio_chips[i],
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&gpio_ranges[i]);
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if (ret)
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if (ret) {
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of_node_put(child);
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return ret;
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}
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++i;
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}
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