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vfio: Stop using iommu_present()

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IOMMU groups have been mandatory for some time now, so a device without
one is necessarily a device without any usable IOMMU, therefore the
iommu_present() check is redundant (or at best unhelpful).

Signed-off-by: Robin Murphy <robin.murphy@arm.com>
Reviewed-by: Jason Gunthorpe <jgg@nvidia.com>
Link: https://lore.kernel.org/r/537103bbd7246574f37f2c88704d7824a3a889f2.1649160714.git.robin.murphy@arm.com
Signed-off-by: Alex Williamson <alex.williamson@redhat.com>
This commit is contained in:
Robin Murphy 2022-05-11 13:12:58 -06:00 committed by Alex Williamson
parent 5acb6cd19d
commit a77109ffca
1 changed files with 3 additions and 3 deletions
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6
drivers/vfio/vfio.c
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@ -745,11 +745,11 @@ static struct vfio_group *vfio_group_find_or_alloc(struct device *dev)
iommu_group = iommu_group_get(dev);
#ifdef CONFIG_VFIO_NOIOMMU
if (!iommu_group && noiommu && !iommu_present(dev->bus)) {
if (!iommu_group && noiommu) {
/*
* With noiommu enabled, create an IOMMU group for devices that
* don't already have one and don't have an iommu_ops on their
* bus. Taint the kernel because we're about to give a DMA
* don't already have one, implying no IOMMU hardware/driver
* exists. Taint the kernel because we're about to give a DMA
* capable device to a user without IOMMU protection.
*/
group = vfio_noiommu_group_alloc(dev, VFIO_NO_IOMMU);