forked from Minki/linux
ocfs2: Count more refcount records in file system fragmentation.
The refcount record calculation in ocfs2_calc_refcount_meta_credits is too optimistic that we can always allocate contiguous clusters and handle an already existed refcount rec as a whole. Actually because of file system fragmentation, we may have the chance to split a refcount record into 3 parts during the transaction. So consider the worst case in record calculation. Cc: stable@kernel.org Signed-off-by: Tao Ma <tao.ma@oracle.com> Signed-off-by: Joel Becker <joel.becker@oracle.com>
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@ -2436,16 +2436,26 @@ static int ocfs2_calc_refcount_meta_credits(struct super_block *sb,
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len = min((u64)cpos + clusters, le64_to_cpu(rec.r_cpos) +
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le32_to_cpu(rec.r_clusters)) - cpos;
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/*
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* If the refcount rec already exist, cool. We just need
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* to check whether there is a split. Otherwise we just need
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* to increase the refcount.
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* If we will insert one, increases recs_add.
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*
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* We record all the records which will be inserted to the
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* same refcount block, so that we can tell exactly whether
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* we need a new refcount block or not.
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*
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* If we will insert a new one, this is easy and only happens
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* during adding refcounted flag to the extent, so we don't
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* have a chance of spliting. We just need one record.
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*
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* If the refcount rec already exists, that would be a little
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* complicated. we may have to:
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* 1) split at the beginning if the start pos isn't aligned.
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* we need 1 more record in this case.
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* 2) split int the end if the end pos isn't aligned.
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* we need 1 more record in this case.
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* 3) split in the middle because of file system fragmentation.
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* we need 2 more records in this case(we can't detect this
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* beforehand, so always think of the worst case).
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*/
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if (rec.r_refcount) {
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recs_add += 2;
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/* Check whether we need a split at the beginning. */
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if (cpos == start_cpos &&
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cpos != le64_to_cpu(rec.r_cpos))
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