uaccess: remove segment_eq
segment_eq is only used to implement uaccess_kernel. Just open code uaccess_kernel in the arch uaccess headers and remove one layer of indirection. Signed-off-by: Christoph Hellwig <hch@lst.de> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Acked-by: Linus Torvalds <torvalds@linux-foundation.org> Acked-by: Greentime Hu <green.hu@gmail.com> Acked-by: Geert Uytterhoeven <geert@linux-m68k.org> Cc: Nick Hu <nickhu@andestech.com> Cc: Vincent Chen <deanbo422@gmail.com> Cc: Paul Walmsley <paul.walmsley@sifive.com> Cc: Palmer Dabbelt <palmer@dabbelt.com> Link: http://lkml.kernel.org/r/20200710135706.537715-5-hch@lst.de Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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Linus Torvalds
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@@ -14,8 +14,7 @@ typedef unsigned long mm_segment_t;
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#define KERNEL_DS MAKE_MM_SEG(0)
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#define USER_DS MAKE_MM_SEG(TASK_SIZE)
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#define segment_eq(a, b) ((a) == (b))
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#define uaccess_kernel() (get_fs() == KERNEL_DS)
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#endif /* __ASSEMBLY__ */
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#endif /* __ASMARC_SEGMENT_H */
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