From 62829b543ec674b4541e2589802accafce5f169d Mon Sep 17 00:00:00 2001
From: fkeyz <73611276+fkeyzuwu@users.noreply.github.com>
Date: Mon, 29 Apr 2024 17:17:31 +0300
Subject: [PATCH] Update Variant documentation comment about class_name

---
 doc/classes/Variant.xml | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/doc/classes/Variant.xml b/doc/classes/Variant.xml
index eb837a46430..b4209332855 100644
--- a/doc/classes/Variant.xml
+++ b/doc/classes/Variant.xml
@@ -42,8 +42,8 @@
 		        # Note that Objects are their own special category.
 		        # To get the name of the underlying Object type, you need the `get_class()` method.
 		        print("foo is a(n) %s" % foo.get_class()) # inject the class name into a formatted string.
-		        # Note also that there is not yet any way to get a script's `class_name` string easily.
-		        # To fetch that value, you can use ProjectSettings.get_global_class_list().
+		        # Note that this does not get the script's `class_name` global identifier.
+		        # If the `class_name` is needed, use `foo.get_script().get_global_name()` instead.
 		[/gdscript]
 		[csharp]
 		Variant foo = 2;