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c6018fc6e7
The code here is supposed to take a signed int and store it in a signed
long long. Unfortunately, the way that the type promotion works with
this conditional statement is that it takes a signed int, type promotes
it to a __u32, and then stores that as a signed long long. The result is
never negative.
This is from static analysis, but I made a little test program just to
test it before I sent the patch:
#include <stdio.h>
int main(void)
{
unsigned long long src = -1ULL;
signed long long dst1, dst2;
int is_signed = 1;
dst1 = is_signed ? *(int *)&src : *(unsigned int *)0;
dst2 = is_signed ? (signed long long)*(int *)&src : *(unsigned int *)0;
printf("%lld\n", dst1);
printf("%lld\n", dst2);
return 0;
}
Fixes:
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.. | ||
accounting | ||
arch | ||
bootconfig | ||
bpf | ||
build | ||
certs | ||
cgroup | ||
counter | ||
debugging | ||
edid | ||
firewire | ||
firmware | ||
gpio | ||
hv | ||
iio | ||
include | ||
io_uring | ||
kvm/kvm_stat | ||
laptop | ||
leds | ||
lib | ||
memory-model | ||
objtool | ||
pci | ||
pcmcia | ||
perf | ||
power | ||
rcu | ||
scripts | ||
spi | ||
testing | ||
thermal | ||
time | ||
tracing | ||
usb | ||
virtio | ||
vm | ||
wmi | ||
Makefile |