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b24413180f
Many source files in the tree are missing licensing information, which makes it harder for compliance tools to determine the correct license. By default all files without license information are under the default license of the kernel, which is GPL version 2. Update the files which contain no license information with the 'GPL-2.0' SPDX license identifier. The SPDX identifier is a legally binding shorthand, which can be used instead of the full boiler plate text. This patch is based on work done by Thomas Gleixner and Kate Stewart and Philippe Ombredanne. How this work was done: Patches were generated and checked against linux-4.14-rc6 for a subset of the use cases: - file had no licensing information it it. - file was a */uapi/* one with no licensing information in it, - file was a */uapi/* one with existing licensing information, Further patches will be generated in subsequent months to fix up cases where non-standard license headers were used, and references to license had to be inferred by heuristics based on keywords. The analysis to determine which SPDX License Identifier to be applied to a file was done in a spreadsheet of side by side results from of the output of two independent scanners (ScanCode & Windriver) producing SPDX tag:value files created by Philippe Ombredanne. Philippe prepared the base worksheet, and did an initial spot review of a few 1000 files. The 4.13 kernel was the starting point of the analysis with 60,537 files assessed. Kate Stewart did a file by file comparison of the scanner results in the spreadsheet to determine which SPDX license identifier(s) to be applied to the file. She confirmed any determination that was not immediately clear with lawyers working with the Linux Foundation. Criteria used to select files for SPDX license identifier tagging was: - Files considered eligible had to be source code files. - Make and config files were included as candidates if they contained >5 lines of source - File already had some variant of a license header in it (even if <5 lines). All documentation files were explicitly excluded. The following heuristics were used to determine which SPDX license identifiers to apply. - when both scanners couldn't find any license traces, file was considered to have no license information in it, and the top level COPYING file license applied. For non */uapi/* files that summary was: SPDX license identifier # files ---------------------------------------------------|------- GPL-2.0 11139 and resulted in the first patch in this series. If that file was a */uapi/* path one, it was "GPL-2.0 WITH Linux-syscall-note" otherwise it was "GPL-2.0". Results of that was: SPDX license identifier # files ---------------------------------------------------|------- GPL-2.0 WITH Linux-syscall-note 930 and resulted in the second patch in this series. - if a file had some form of licensing information in it, and was one of the */uapi/* ones, it was denoted with the Linux-syscall-note if any GPL family license was found in the file or had no licensing in it (per prior point). Results summary: SPDX license identifier # files ---------------------------------------------------|------ GPL-2.0 WITH Linux-syscall-note 270 GPL-2.0+ WITH Linux-syscall-note 169 ((GPL-2.0 WITH Linux-syscall-note) OR BSD-2-Clause) 21 ((GPL-2.0 WITH Linux-syscall-note) OR BSD-3-Clause) 17 LGPL-2.1+ WITH Linux-syscall-note 15 GPL-1.0+ WITH Linux-syscall-note 14 ((GPL-2.0+ WITH Linux-syscall-note) OR BSD-3-Clause) 5 LGPL-2.0+ WITH Linux-syscall-note 4 LGPL-2.1 WITH Linux-syscall-note 3 ((GPL-2.0 WITH Linux-syscall-note) OR MIT) 3 ((GPL-2.0 WITH Linux-syscall-note) AND MIT) 1 and that resulted in the third patch in this series. - when the two scanners agreed on the detected license(s), that became the concluded license(s). - when there was disagreement between the two scanners (one detected a license but the other didn't, or they both detected different licenses) a manual inspection of the file occurred. - In most cases a manual inspection of the information in the file resulted in a clear resolution of the license that should apply (and which scanner probably needed to revisit its heuristics). - When it was not immediately clear, the license identifier was confirmed with lawyers working with the Linux Foundation. - If there was any question as to the appropriate license identifier, the file was flagged for further research and to be revisited later in time. In total, over 70 hours of logged manual review was done on the spreadsheet to determine the SPDX license identifiers to apply to the source files by Kate, Philippe, Thomas and, in some cases, confirmation by lawyers working with the Linux Foundation. Kate also obtained a third independent scan of the 4.13 code base from FOSSology, and compared selected files where the other two scanners disagreed against that SPDX file, to see if there was new insights. The Windriver scanner is based on an older version of FOSSology in part, so they are related. Thomas did random spot checks in about 500 files from the spreadsheets for the uapi headers and agreed with SPDX license identifier in the files he inspected. For the non-uapi files Thomas did random spot checks in about 15000 files. In initial set of patches against 4.14-rc6, 3 files were found to have copy/paste license identifier errors, and have been fixed to reflect the correct identifier. Additionally Philippe spent 10 hours this week doing a detailed manual inspection and review of the 12,461 patched files from the initial patch version early this week with: - a full scancode scan run, collecting the matched texts, detected license ids and scores - reviewing anything where there was a license detected (about 500+ files) to ensure that the applied SPDX license was correct - reviewing anything where there was no detection but the patch license was not GPL-2.0 WITH Linux-syscall-note to ensure that the applied SPDX license was correct This produced a worksheet with 20 files needing minor correction. This worksheet was then exported into 3 different .csv files for the different types of files to be modified. These .csv files were then reviewed by Greg. Thomas wrote a script to parse the csv files and add the proper SPDX tag to the file, in the format that the file expected. This script was further refined by Greg based on the output to detect more types of files automatically and to distinguish between header and source .c files (which need different comment types.) Finally Greg ran the script using the .csv files to generate the patches. Reviewed-by: Kate Stewart <kstewart@linuxfoundation.org> Reviewed-by: Philippe Ombredanne <pombredanne@nexb.com> Reviewed-by: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
347 lines
11 KiB
ArmAsm
347 lines
11 KiB
ArmAsm
/* SPDX-License-Identifier: GPL-2.0 */
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/*
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* arch/alpha/lib/stxncpy.S
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* Contributed by Richard Henderson (rth@tamu.edu)
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*
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* Copy no more than COUNT bytes of the null-terminated string from
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* SRC to DST.
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*
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* This is an internal routine used by strncpy, stpncpy, and strncat.
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* As such, it uses special linkage conventions to make implementation
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* of these public functions more efficient.
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*
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* On input:
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* t9 = return address
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* a0 = DST
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* a1 = SRC
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* a2 = COUNT
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*
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* Furthermore, COUNT may not be zero.
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*
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* On output:
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* t0 = last word written
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* t10 = bitmask (with one bit set) indicating the byte position of
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* the end of the range specified by COUNT
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* t12 = bitmask (with one bit set) indicating the last byte written
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* a0 = unaligned address of the last *word* written
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* a2 = the number of full words left in COUNT
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*
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* Furthermore, v0, a3-a5, t11, and $at are untouched.
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*/
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#include <asm/regdef.h>
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.set noat
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.set noreorder
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.text
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/* There is a problem with either gdb (as of 4.16) or gas (as of 2.7) that
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doesn't like putting the entry point for a procedure somewhere in the
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middle of the procedure descriptor. Work around this by putting the
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aligned copy in its own procedure descriptor */
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.ent stxncpy_aligned
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.align 3
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stxncpy_aligned:
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.frame sp, 0, t9, 0
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.prologue 0
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/* On entry to this basic block:
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t0 == the first destination word for masking back in
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t1 == the first source word. */
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/* Create the 1st output word and detect 0's in the 1st input word. */
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lda t2, -1 # e1 : build a mask against false zero
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mskqh t2, a1, t2 # e0 : detection in the src word
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mskqh t1, a1, t3 # e0 :
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ornot t1, t2, t2 # .. e1 :
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mskql t0, a1, t0 # e0 : assemble the first output word
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cmpbge zero, t2, t8 # .. e1 : bits set iff null found
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or t0, t3, t0 # e0 :
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beq a2, $a_eoc # .. e1 :
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bne t8, $a_eos # .. e1 :
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/* On entry to this basic block:
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t0 == a source word not containing a null. */
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$a_loop:
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stq_u t0, 0(a0) # e0 :
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addq a0, 8, a0 # .. e1 :
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ldq_u t0, 0(a1) # e0 :
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addq a1, 8, a1 # .. e1 :
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subq a2, 1, a2 # e0 :
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cmpbge zero, t0, t8 # .. e1 (stall)
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beq a2, $a_eoc # e1 :
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beq t8, $a_loop # e1 :
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/* Take care of the final (partial) word store. At this point
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the end-of-count bit is set in t8 iff it applies.
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On entry to this basic block we have:
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t0 == the source word containing the null
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t8 == the cmpbge mask that found it. */
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$a_eos:
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negq t8, t12 # e0 : find low bit set
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and t8, t12, t12 # e1 (stall)
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/* For the sake of the cache, don't read a destination word
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if we're not going to need it. */
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and t12, 0x80, t6 # e0 :
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bne t6, 1f # .. e1 (zdb)
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/* We're doing a partial word store and so need to combine
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our source and original destination words. */
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ldq_u t1, 0(a0) # e0 :
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subq t12, 1, t6 # .. e1 :
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or t12, t6, t8 # e0 :
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unop #
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zapnot t0, t8, t0 # e0 : clear src bytes > null
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zap t1, t8, t1 # .. e1 : clear dst bytes <= null
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or t0, t1, t0 # e1 :
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1: stq_u t0, 0(a0) # e0 :
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ret (t9) # e1 :
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/* Add the end-of-count bit to the eos detection bitmask. */
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$a_eoc:
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or t10, t8, t8
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br $a_eos
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.end stxncpy_aligned
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.align 3
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.ent __stxncpy
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.globl __stxncpy
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__stxncpy:
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.frame sp, 0, t9, 0
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.prologue 0
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/* Are source and destination co-aligned? */
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xor a0, a1, t1 # e0 :
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and a0, 7, t0 # .. e1 : find dest misalignment
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and t1, 7, t1 # e0 :
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addq a2, t0, a2 # .. e1 : bias count by dest misalignment
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subq a2, 1, a2 # e0 :
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and a2, 7, t2 # e1 :
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srl a2, 3, a2 # e0 : a2 = loop counter = (count - 1)/8
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addq zero, 1, t10 # .. e1 :
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sll t10, t2, t10 # e0 : t10 = bitmask of last count byte
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bne t1, $unaligned # .. e1 :
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/* We are co-aligned; take care of a partial first word. */
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ldq_u t1, 0(a1) # e0 : load first src word
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addq a1, 8, a1 # .. e1 :
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beq t0, stxncpy_aligned # avoid loading dest word if not needed
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ldq_u t0, 0(a0) # e0 :
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br stxncpy_aligned # .. e1 :
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/* The source and destination are not co-aligned. Align the destination
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and cope. We have to be very careful about not reading too much and
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causing a SEGV. */
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.align 3
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$u_head:
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/* We know just enough now to be able to assemble the first
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full source word. We can still find a zero at the end of it
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that prevents us from outputting the whole thing.
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On entry to this basic block:
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t0 == the first dest word, unmasked
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t1 == the shifted low bits of the first source word
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t6 == bytemask that is -1 in dest word bytes */
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ldq_u t2, 8(a1) # e0 : load second src word
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addq a1, 8, a1 # .. e1 :
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mskql t0, a0, t0 # e0 : mask trailing garbage in dst
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extqh t2, a1, t4 # e0 :
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or t1, t4, t1 # e1 : first aligned src word complete
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mskqh t1, a0, t1 # e0 : mask leading garbage in src
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or t0, t1, t0 # e0 : first output word complete
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or t0, t6, t6 # e1 : mask original data for zero test
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cmpbge zero, t6, t8 # e0 :
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beq a2, $u_eocfin # .. e1 :
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lda t6, -1 # e0 :
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bne t8, $u_final # .. e1 :
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mskql t6, a1, t6 # e0 : mask out bits already seen
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nop # .. e1 :
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stq_u t0, 0(a0) # e0 : store first output word
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or t6, t2, t2 # .. e1 :
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cmpbge zero, t2, t8 # e0 : find nulls in second partial
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addq a0, 8, a0 # .. e1 :
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subq a2, 1, a2 # e0 :
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bne t8, $u_late_head_exit # .. e1 :
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/* Finally, we've got all the stupid leading edge cases taken care
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of and we can set up to enter the main loop. */
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extql t2, a1, t1 # e0 : position hi-bits of lo word
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beq a2, $u_eoc # .. e1 :
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ldq_u t2, 8(a1) # e0 : read next high-order source word
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addq a1, 8, a1 # .. e1 :
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extqh t2, a1, t0 # e0 : position lo-bits of hi word (stall)
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cmpbge zero, t2, t8 # .. e1 :
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nop # e0 :
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bne t8, $u_eos # .. e1 :
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/* Unaligned copy main loop. In order to avoid reading too much,
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the loop is structured to detect zeros in aligned source words.
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This has, unfortunately, effectively pulled half of a loop
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iteration out into the head and half into the tail, but it does
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prevent nastiness from accumulating in the very thing we want
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to run as fast as possible.
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On entry to this basic block:
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t0 == the shifted low-order bits from the current source word
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t1 == the shifted high-order bits from the previous source word
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t2 == the unshifted current source word
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We further know that t2 does not contain a null terminator. */
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.align 3
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$u_loop:
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or t0, t1, t0 # e0 : current dst word now complete
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subq a2, 1, a2 # .. e1 : decrement word count
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stq_u t0, 0(a0) # e0 : save the current word
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addq a0, 8, a0 # .. e1 :
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extql t2, a1, t1 # e0 : extract high bits for next time
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beq a2, $u_eoc # .. e1 :
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ldq_u t2, 8(a1) # e0 : load high word for next time
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addq a1, 8, a1 # .. e1 :
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nop # e0 :
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cmpbge zero, t2, t8 # e1 : test new word for eos (stall)
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extqh t2, a1, t0 # e0 : extract low bits for current word
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beq t8, $u_loop # .. e1 :
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/* We've found a zero somewhere in the source word we just read.
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If it resides in the lower half, we have one (probably partial)
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word to write out, and if it resides in the upper half, we
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have one full and one partial word left to write out.
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On entry to this basic block:
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t0 == the shifted low-order bits from the current source word
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t1 == the shifted high-order bits from the previous source word
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t2 == the unshifted current source word. */
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$u_eos:
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or t0, t1, t0 # e0 : first (partial) source word complete
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nop # .. e1 :
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cmpbge zero, t0, t8 # e0 : is the null in this first bit?
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bne t8, $u_final # .. e1 (zdb)
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stq_u t0, 0(a0) # e0 : the null was in the high-order bits
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addq a0, 8, a0 # .. e1 :
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subq a2, 1, a2 # e1 :
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$u_late_head_exit:
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extql t2, a1, t0 # .. e0 :
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cmpbge zero, t0, t8 # e0 :
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or t8, t10, t6 # e1 :
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cmoveq a2, t6, t8 # e0 :
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nop # .. e1 :
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/* Take care of a final (probably partial) result word.
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On entry to this basic block:
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t0 == assembled source word
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t8 == cmpbge mask that found the null. */
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$u_final:
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negq t8, t6 # e0 : isolate low bit set
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and t6, t8, t12 # e1 :
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and t12, 0x80, t6 # e0 : avoid dest word load if we can
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bne t6, 1f # .. e1 (zdb)
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ldq_u t1, 0(a0) # e0 :
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subq t12, 1, t6 # .. e1 :
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or t6, t12, t8 # e0 :
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zapnot t0, t8, t0 # .. e1 : kill source bytes > null
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zap t1, t8, t1 # e0 : kill dest bytes <= null
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or t0, t1, t0 # e1 :
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1: stq_u t0, 0(a0) # e0 :
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ret (t9) # .. e1 :
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/* Got to end-of-count before end of string.
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On entry to this basic block:
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t1 == the shifted high-order bits from the previous source word */
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$u_eoc:
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and a1, 7, t6 # e1 :
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sll t10, t6, t6 # e0 :
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and t6, 0xff, t6 # e0 :
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bne t6, 1f # .. e1 :
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ldq_u t2, 8(a1) # e0 : load final src word
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nop # .. e1 :
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extqh t2, a1, t0 # e0 : extract low bits for last word
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or t1, t0, t1 # e1 :
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1: cmpbge zero, t1, t8
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mov t1, t0
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$u_eocfin: # end-of-count, final word
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or t10, t8, t8
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br $u_final
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/* Unaligned copy entry point. */
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.align 3
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$unaligned:
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ldq_u t1, 0(a1) # e0 : load first source word
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and a0, 7, t4 # .. e1 : find dest misalignment
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and a1, 7, t5 # e0 : find src misalignment
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/* Conditionally load the first destination word and a bytemask
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with 0xff indicating that the destination byte is sacrosanct. */
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mov zero, t0 # .. e1 :
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mov zero, t6 # e0 :
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beq t4, 1f # .. e1 :
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ldq_u t0, 0(a0) # e0 :
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lda t6, -1 # .. e1 :
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mskql t6, a0, t6 # e0 :
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subq a1, t4, a1 # .. e1 : sub dest misalignment from src addr
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/* If source misalignment is larger than dest misalignment, we need
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extra startup checks to avoid SEGV. */
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1: cmplt t4, t5, t12 # e1 :
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extql t1, a1, t1 # .. e0 : shift src into place
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lda t2, -1 # e0 : for creating masks later
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beq t12, $u_head # .. e1 :
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extql t2, a1, t2 # e0 :
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cmpbge zero, t1, t8 # .. e1 : is there a zero?
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andnot t2, t6, t2 # e0 : dest mask for a single word copy
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or t8, t10, t5 # .. e1 : test for end-of-count too
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cmpbge zero, t2, t3 # e0 :
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cmoveq a2, t5, t8 # .. e1 :
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andnot t8, t3, t8 # e0 :
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beq t8, $u_head # .. e1 (zdb)
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/* At this point we've found a zero in the first partial word of
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the source. We need to isolate the valid source data and mask
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it into the original destination data. (Incidentally, we know
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that we'll need at least one byte of that original dest word.) */
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ldq_u t0, 0(a0) # e0 :
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negq t8, t6 # .. e1 : build bitmask of bytes <= zero
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mskqh t1, t4, t1 # e0 :
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and t6, t8, t12 # .. e1 :
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subq t12, 1, t6 # e0 :
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or t6, t12, t8 # e1 :
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zapnot t2, t8, t2 # e0 : prepare source word; mirror changes
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zapnot t1, t8, t1 # .. e1 : to source validity mask
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andnot t0, t2, t0 # e0 : zero place for source to reside
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or t0, t1, t0 # e1 : and put it there
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stq_u t0, 0(a0) # e0 :
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ret (t9) # .. e1 :
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.end __stxncpy
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