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05296e7535
Paul noticed that in the (periods >= LOAD_AVG_MAX_N) case in
__accumulate_sum(), the returned contribution value (LOAD_AVG_MAX) is
incorrect.
This is because at this point, the decay_load() on the old state --
the first step in accumulate_sum() -- will not have resulted in 0, and
will therefore result in a sum larger than the maximum value of our
series. Obviously broken.
Note that:
decay_load(LOAD_AVG_MAX, LOAD_AVG_MAX_N) =
1 (345 / 32)
47742 * - ^ = ~27
2
Not to mention that any further contribution from the d3 segment (our
new period) would also push it over the maximum.
Solve this by noting that we can write our c2 term:
p
c2 = 1024 \Sum y^n
n=1
In terms of our maximum value:
inf inf p
max = 1024 \Sum y^n = 1024 ( \Sum y^n + \Sum y^n + y^0 )
n=0 n=p+1 n=1
Further note that:
inf inf inf
( \Sum y^n ) y^p = \Sum y^(n+p) = \Sum y^n
n=0 n=0 n=p
Combined that gives us:
p
c2 = 1024 \Sum y^n
n=1
inf inf
= 1024 ( \Sum y^n - \Sum y^n - y^0 )
n=0 n=p+1
= max - (max y^(p+1)) - 1024
Further simplify things by dealing with p=0 early on.
Reported-by: Paul Turner <pjt@google.com>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Mike Galbraith <efault@gmx.de>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Yuyang Du <yuyang.du@intel.com>
Cc: linux-kernel@vger.kernel.org
Fixes:
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|---|---|---|
| .. | ||
| autogroup.c | ||
| autogroup.h | ||
| clock.c | ||
| completion.c | ||
| core.c | ||
| cpuacct.c | ||
| cpuacct.h | ||
| cpudeadline.c | ||
| cpudeadline.h | ||
| cpufreq_schedutil.c | ||
| cpufreq.c | ||
| cpupri.c | ||
| cpupri.h | ||
| cputime.c | ||
| deadline.c | ||
| debug.c | ||
| fair.c | ||
| features.h | ||
| idle_task.c | ||
| idle.c | ||
| loadavg.c | ||
| Makefile | ||
| rt.c | ||
| sched.h | ||
| stats.c | ||
| stats.h | ||
| stop_task.c | ||
| swait.c | ||
| topology.c | ||
| wait.c | ||