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btrfs: Be explicit about usage of min()

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__btrfs_alloc_chunk contains code which boils down to:

    ndevs = min(ndevs, devs_max)

It's conditional upon devs_max not being 0. However, it cannot really be 0
since it's always set to either BTRFS_MAX_DEVS_SYS_CHUNK or
BTRFS_MAX_DEVS(fs_info->chunk_root). So eliminate the condition check and use
min explicitly. This has no functional changes.

Signed-off-by: Nikolay Borisov <nborisov@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Nikolay Borisov 2017-06-27 10:02:26 +03:00 committed by David Sterba
parent e5600fd6fc
commit f148ef4d3a
1 changed files with 2 additions and 2 deletions
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4
fs/btrfs/volumes.c
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@ -4769,8 +4769,8 @@ static int __btrfs_alloc_chunk(struct btrfs_trans_handle *trans,
goto error;
}
if (devs_max && ndevs > devs_max)
ndevs = devs_max;
ndevs = min(ndevs, devs_max);
/*
* the primary goal is to maximize the number of stripes, so use as many
* devices as possible, even if the stripes are not maximum sized.