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rcu: Clarify memory-ordering properties of grace-period primitives
This commit explicitly states the memory-ordering properties of the RCU grace-period primitives. Although these properties were in some sense implied by the fundmental property of RCU ("a grace period must wait for all pre-existing RCU read-side critical sections to complete"), stating it explicitly will be a great labor-saving device. Reported-by: Oleg Nesterov <oleg@redhat.com> Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com> Reviewed-by: Oleg Nesterov <oleg@redhat.com>
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@ -90,6 +90,25 @@ extern void do_trace_rcu_torture_read(char *rcutorturename,
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* that started after call_rcu() was invoked. RCU read-side critical
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* sections are delimited by rcu_read_lock() and rcu_read_unlock(),
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* and may be nested.
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*
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* Note that all CPUs must agree that the grace period extended beyond
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* all pre-existing RCU read-side critical section. On systems with more
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* than one CPU, this means that when "func()" is invoked, each CPU is
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* guaranteed to have executed a full memory barrier since the end of its
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* last RCU read-side critical section whose beginning preceded the call
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* to call_rcu(). It also means that each CPU executing an RCU read-side
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* critical section that continues beyond the start of "func()" must have
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* executed a memory barrier after the call_rcu() but before the beginning
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* of that RCU read-side critical section. Note that these guarantees
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* include CPUs that are offline, idle, or executing in user mode, as
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* well as CPUs that are executing in the kernel.
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*
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* Furthermore, if CPU A invoked call_rcu() and CPU B invoked the
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* resulting RCU callback function "func()", then both CPU A and CPU B are
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* guaranteed to execute a full memory barrier during the time interval
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* between the call to call_rcu() and the invocation of "func()" -- even
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* if CPU A and CPU B are the same CPU (but again only if the system has
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* more than one CPU).
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*/
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extern void call_rcu(struct rcu_head *head,
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void (*func)(struct rcu_head *head));
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@ -118,6 +137,9 @@ extern void call_rcu(struct rcu_head *head,
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* OR
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* - rcu_read_lock_bh() and rcu_read_unlock_bh(), if in process context.
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* These may be nested.
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*
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* See the description of call_rcu() for more detailed information on
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* memory ordering guarantees.
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*/
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extern void call_rcu_bh(struct rcu_head *head,
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void (*func)(struct rcu_head *head));
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@ -137,6 +159,9 @@ extern void call_rcu_bh(struct rcu_head *head,
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* OR
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* anything that disables preemption.
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* These may be nested.
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*
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* See the description of call_rcu() for more detailed information on
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* memory ordering guarantees.
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*/
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extern void call_rcu_sched(struct rcu_head *head,
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void (*func)(struct rcu_head *rcu));
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@ -2228,10 +2228,28 @@ static inline int rcu_blocking_is_gp(void)
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* rcu_read_lock_sched().
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*
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* This means that all preempt_disable code sequences, including NMI and
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* hardware-interrupt handlers, in progress on entry will have completed
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* before this primitive returns. However, this does not guarantee that
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* softirq handlers will have completed, since in some kernels, these
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* handlers can run in process context, and can block.
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* non-threaded hardware-interrupt handlers, in progress on entry will
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* have completed before this primitive returns. However, this does not
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* guarantee that softirq handlers will have completed, since in some
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* kernels, these handlers can run in process context, and can block.
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*
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* Note that this guarantee implies further memory-ordering guarantees.
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* On systems with more than one CPU, when synchronize_sched() returns,
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* each CPU is guaranteed to have executed a full memory barrier since the
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* end of its last RCU-sched read-side critical section whose beginning
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* preceded the call to synchronize_sched(). In addition, each CPU having
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* an RCU read-side critical section that extends beyond the return from
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* synchronize_sched() is guaranteed to have executed a full memory barrier
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* after the beginning of synchronize_sched() and before the beginning of
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* that RCU read-side critical section. Note that these guarantees include
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* CPUs that are offline, idle, or executing in user mode, as well as CPUs
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* that are executing in the kernel.
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*
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* Furthermore, if CPU A invoked synchronize_sched(), which returned
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* to its caller on CPU B, then both CPU A and CPU B are guaranteed
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* to have executed a full memory barrier during the execution of
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* synchronize_sched() -- even if CPU A and CPU B are the same CPU (but
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* again only if the system has more than one CPU).
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*
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* This primitive provides the guarantees made by the (now removed)
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* synchronize_kernel() API. In contrast, synchronize_rcu() only
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@ -2259,6 +2277,9 @@ EXPORT_SYMBOL_GPL(synchronize_sched);
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* read-side critical sections have completed. RCU read-side critical
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* sections are delimited by rcu_read_lock_bh() and rcu_read_unlock_bh(),
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* and may be nested.
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*
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* See the description of synchronize_sched() for more detailed information
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* on memory ordering guarantees.
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*/
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void synchronize_rcu_bh(void)
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{
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@ -670,6 +670,9 @@ EXPORT_SYMBOL_GPL(kfree_call_rcu);
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* concurrently with new RCU read-side critical sections that began while
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* synchronize_rcu() was waiting. RCU read-side critical sections are
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* delimited by rcu_read_lock() and rcu_read_unlock(), and may be nested.
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*
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* See the description of synchronize_sched() for more detailed information
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* on memory ordering guarantees.
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*/
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void synchronize_rcu(void)
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{
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@ -875,6 +878,11 @@ EXPORT_SYMBOL_GPL(synchronize_rcu_expedited);
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/**
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* rcu_barrier - Wait until all in-flight call_rcu() callbacks complete.
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*
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* Note that this primitive does not necessarily wait for an RCU grace period
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* to complete. For example, if there are no RCU callbacks queued anywhere
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* in the system, then rcu_barrier() is within its rights to return
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* immediately, without waiting for anything, much less an RCU grace period.
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*/
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void rcu_barrier(void)
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{
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