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lib/vsprintf.c: reduce stack use in number()
At least since the initial git commit, when base was passed as a separate parameter, number() has only been called with bases 8, 10 and 16. I'm guessing that 66 was to accommodate 64 0/1, a sign and a '\0', but the buffer is only used for the actual digits. Octal digits carry 3 bits of information, so 24 is enough. Spell that 3*sizeof(num) so one less place needs to be changed should long long ever be 128 bits. Also remove the commented-out code that would handle an arbitrary base. Signed-off-by: Rasmus Villemoes <linux@rasmusvillemoes.dk> Cc: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Tejun Heo <tj@kernel.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -386,7 +386,7 @@ char *number(char *buf, char *end, unsigned long long num,
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/* we are called with base 8, 10 or 16, only, thus don't need "G..." */
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static const char digits[16] = "0123456789ABCDEF"; /* "GHIJKLMNOPQRSTUVWXYZ"; */
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char tmp[66];
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char tmp[3 * sizeof(num)];
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char sign;
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char locase;
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int need_pfx = ((spec.flags & SPECIAL) && spec.base != 10);
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@ -423,11 +423,6 @@ char *number(char *buf, char *end, unsigned long long num,
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i = 0;
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if (num < spec.base)
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tmp[i++] = digits[num] | locase;
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/* Generic code, for any base:
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else do {
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tmp[i++] = (digits[do_div(num,base)] | locase);
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} while (num != 0);
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*/
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else if (spec.base != 10) { /* 8 or 16 */
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int mask = spec.base - 1;
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int shift = 3;
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