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scsi: ufs: Simplify a condition

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We know that "check_for_bkops" is non-zero on this side of the || because
it was checked on the other side.

Link: https://lore.kernel.org/r/20191213104935.wgpq2epaz6zh5zus@kili.mountain
Reviewed-by: Bart Van Assche <bvanassche@acm.org>
Reviewed-by: Avri Altman <avri.altman@wdc.com>
Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com>
Signed-off-by: Martin K. Petersen <martin.petersen@oracle.com>
This commit is contained in:
Dan Carpenter 2019-12-13 13:49:35 +03:00 committed by Martin K. Petersen
parent bb14dd1564
commit dc30c9e6d6
1 changed files with 1 additions and 2 deletions
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3
drivers/scsi/ufs/ufshcd.c
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@ -7684,8 +7684,7 @@ static int ufshcd_link_state_transition(struct ufs_hba *hba,
* turning off the link would also turn off the device.
*/
else if ((req_link_state == UIC_LINK_OFF_STATE) &&
(!check_for_bkops || (check_for_bkops &&
!hba->auto_bkops_enabled))) {
(!check_for_bkops || !hba->auto_bkops_enabled)) {
/*
* Let's make sure that link is in low power mode, we are doing
* this currently by putting the link in Hibern8. Otherway to