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Btrfs: fix deadlock in btrfs_commit_transaction
We calculate timeout (either 1 or MAX_SCHEDULE_TIMEOUT) based on whether num_writers > 1 or should_grow at the top of the loop. Then, much much later, we wait for that timeout if either num_writers or should_grow is true. However, it's possible for a racing process (calling btrfs_end_transaction()) to decrement num_writers such that we wait forever instead of for 1. Fix this by deciding how long to wait when we wait. Include a smp_mb() before checking if the waitqueue is active to ensure the num_writers is visible. Signed-off-by: Sage Weil <sage@newdream.net> Signed-off-by: Chris Mason <chris.mason@oracle.com>
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@ -402,6 +402,7 @@ static int __btrfs_end_transaction(struct btrfs_trans_handle *trans,
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WARN_ON(cur_trans->num_writers < 1);
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cur_trans->num_writers--;
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smp_mb();
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if (waitqueue_active(&cur_trans->writer_wait))
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wake_up(&cur_trans->writer_wait);
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put_transaction(cur_trans);
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@ -1010,7 +1011,6 @@ int btrfs_commit_transaction(struct btrfs_trans_handle *trans,
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struct btrfs_root *root)
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{
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unsigned long joined = 0;
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unsigned long timeout = 1;
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struct btrfs_transaction *cur_trans;
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struct btrfs_transaction *prev_trans = NULL;
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DEFINE_WAIT(wait);
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@ -1081,11 +1081,6 @@ int btrfs_commit_transaction(struct btrfs_trans_handle *trans,
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snap_pending = 1;
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WARN_ON(cur_trans != trans->transaction);
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if (cur_trans->num_writers > 1)
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timeout = MAX_SCHEDULE_TIMEOUT;
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else if (should_grow)
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timeout = 1;
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mutex_unlock(&root->fs_info->trans_mutex);
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if (flush_on_commit || snap_pending) {
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@ -1107,8 +1102,10 @@ int btrfs_commit_transaction(struct btrfs_trans_handle *trans,
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TASK_UNINTERRUPTIBLE);
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smp_mb();
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if (cur_trans->num_writers > 1 || should_grow)
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schedule_timeout(timeout);
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if (cur_trans->num_writers > 1)
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schedule_timeout(MAX_SCHEDULE_TIMEOUT);
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else if (should_grow)
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schedule_timeout(1);
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mutex_lock(&root->fs_info->trans_mutex);
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finish_wait(&cur_trans->writer_wait, &wait);
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