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btrfs: avoid double put of block group when emptying cluster
It's wrong calling btrfs_put_block_group in
__btrfs_return_cluster_to_free_space if the block group passed is
different than the block group the cluster represents. As this means the
cluster doesn't have a reference to the passed block group. This results
in double put and a use-after-free bug.
Fix this by simply bailing if the block group we passed in does not
match the block group on the cluster.
Fixes: fa9c0d795f
("Btrfs: rework allocation clustering")
CC: stable@vger.kernel.org # 4.4+
Signed-off-by: Josef Bacik <josef@toxicpanda.com>
Reviewed-by: David Sterba <dsterba@suse.com>
[ update changelog ]
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
parent
3660d0bcdb
commit
95c85fba1f
@ -2801,8 +2801,10 @@ static void __btrfs_return_cluster_to_free_space(
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struct rb_node *node;
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spin_lock(&cluster->lock);
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if (cluster->block_group != block_group)
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goto out;
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if (cluster->block_group != block_group) {
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spin_unlock(&cluster->lock);
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return;
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}
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cluster->block_group = NULL;
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cluster->window_start = 0;
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@ -2840,8 +2842,6 @@ static void __btrfs_return_cluster_to_free_space(
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entry->offset, &entry->offset_index, bitmap);
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}
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cluster->root = RB_ROOT;
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out:
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spin_unlock(&cluster->lock);
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btrfs_put_block_group(block_group);
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}
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