thunderbolt: Use 32-bit writes when writing ring producer/consumer

The register access should be using 32-bit reads/writes according to the
datasheet. With the previous generation hardware 16-bit writes have been
working but starting with ICL this is not the case anymore so fix
producer/consumer register update to use correct width register address.

Signed-off-by: Mika Westerberg <mika.westerberg@linux.intel.com>
Reviewed-by: Yehezkel Bernat <YehezkelShB@gmail.com>
Tested-by: Mario Limonciello <mario.limonciello@dell.com>
This commit is contained in:
Mika Westerberg 2018-07-04 08:46:07 +03:00
parent f437c24bf6
commit 943795219d

View File

@ -143,9 +143,20 @@ static void __iomem *ring_options_base(struct tb_ring *ring)
return io;
}
static void ring_iowrite16desc(struct tb_ring *ring, u32 value, u32 offset)
static void ring_iowrite_cons(struct tb_ring *ring, u16 cons)
{
iowrite16(value, ring_desc_base(ring) + offset);
/*
* The other 16-bits in the register is read-only and writes to it
* are ignored by the hardware so we can save one ioread32() by
* filling the read-only bits with zeroes.
*/
iowrite32(cons, ring_desc_base(ring) + 8);
}
static void ring_iowrite_prod(struct tb_ring *ring, u16 prod)
{
/* See ring_iowrite_cons() above for explanation */
iowrite32(prod << 16, ring_desc_base(ring) + 8);
}
static void ring_iowrite32desc(struct tb_ring *ring, u32 value, u32 offset)
@ -197,7 +208,10 @@ static void ring_write_descriptors(struct tb_ring *ring)
descriptor->sof = frame->sof;
}
ring->head = (ring->head + 1) % ring->size;
ring_iowrite16desc(ring, ring->head, ring->is_tx ? 10 : 8);
if (ring->is_tx)
ring_iowrite_prod(ring, ring->head);
else
ring_iowrite_cons(ring, ring->head);
}
}
@ -662,7 +676,7 @@ void tb_ring_stop(struct tb_ring *ring)
ring_iowrite32options(ring, 0, 0);
ring_iowrite64desc(ring, 0, 0);
ring_iowrite16desc(ring, 0, ring->is_tx ? 10 : 8);
ring_iowrite32desc(ring, 0, 8);
ring_iowrite32desc(ring, 0, 12);
ring->head = 0;
ring->tail = 0;