mirror of
https://github.com/torvalds/linux.git
synced 2024-11-25 05:32:00 +00:00
mul_u64_u64_div_u64: increase precision by conditionally swapping a and b
As indicated in the added comment, the algorithm works better if b is big. As multiplication is commutative, a and b can be swapped. Do this if a is bigger than b. Link: https://lkml.kernel.org/r/20240303092408.662449-2-u.kleine-koenig@pengutronix.de Signed-off-by: Uwe Kleine-König <u.kleine-koenig@pengutronix.de> Tested-by: Biju Das <biju.das.jz@bp.renesas.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
This commit is contained in:
parent
4bb7be96fc
commit
8c86fb68ff
@ -22,6 +22,7 @@
|
||||
#include <linux/export.h>
|
||||
#include <linux/math.h>
|
||||
#include <linux/math64.h>
|
||||
#include <linux/minmax.h>
|
||||
#include <linux/log2.h>
|
||||
|
||||
/* Not needed on 64bit architectures */
|
||||
@ -190,6 +191,20 @@ u64 mul_u64_u64_div_u64(u64 a, u64 b, u64 c)
|
||||
|
||||
/* can a * b overflow ? */
|
||||
if (ilog2(a) + ilog2(b) > 62) {
|
||||
/*
|
||||
* Note that the algorithm after the if block below might lose
|
||||
* some precision and the result is more exact for b > a. So
|
||||
* exchange a and b if a is bigger than b.
|
||||
*
|
||||
* For example with a = 43980465100800, b = 100000000, c = 1000000000
|
||||
* the below calculation doesn't modify b at all because div == 0
|
||||
* and then shift becomes 45 + 26 - 62 = 9 and so the result
|
||||
* becomes 4398035251080. However with a and b swapped the exact
|
||||
* result is calculated (i.e. 4398046510080).
|
||||
*/
|
||||
if (a > b)
|
||||
swap(a, b);
|
||||
|
||||
/*
|
||||
* (b * a) / c is equal to
|
||||
*
|
||||
|
Loading…
Reference in New Issue
Block a user