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netfilter: Use correct return for seq_show functions
Using seq_has_overflowed doesn't produce the right return value. Either 0 or -1 is, but 0 is much more common and works well when seq allocation retries. I believe this doesn't matter as the initial allocation is always sufficient, this is just a correctness patch. Miscellanea: o Don't use strlen, use *ptr to determine if a string should be emitted like all the other tests here o Delete unnecessary return statements Signed-off-by: Joe Perches <joe@perches.com> Signed-off-by: Pablo Neira Ayuso <pablo@netfilter.org>
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@ -1257,7 +1257,7 @@ static int seq_show(struct seq_file *s, void *v)
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inst->copy_mode, inst->copy_range,
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inst->queue_dropped, inst->queue_user_dropped,
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inst->id_sequence, 1);
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return seq_has_overflowed(s);
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return 0;
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}
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static const struct seq_operations nfqnl_seq_ops = {
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@ -947,11 +947,9 @@ static int xt_table_seq_show(struct seq_file *seq, void *v)
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{
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struct xt_table *table = list_entry(v, struct xt_table, list);
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if (strlen(table->name)) {
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if (*table->name)
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seq_printf(seq, "%s\n", table->name);
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return seq_has_overflowed(seq);
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} else
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return 0;
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return 0;
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}
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static const struct seq_operations xt_table_seq_ops = {
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@ -1087,10 +1085,8 @@ static int xt_match_seq_show(struct seq_file *seq, void *v)
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if (trav->curr == trav->head)
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return 0;
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match = list_entry(trav->curr, struct xt_match, list);
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if (*match->name == '\0')
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return 0;
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seq_printf(seq, "%s\n", match->name);
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return seq_has_overflowed(seq);
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if (*match->name)
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seq_printf(seq, "%s\n", match->name);
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}
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return 0;
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}
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@ -1142,10 +1138,8 @@ static int xt_target_seq_show(struct seq_file *seq, void *v)
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if (trav->curr == trav->head)
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return 0;
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target = list_entry(trav->curr, struct xt_target, list);
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if (*target->name == '\0')
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return 0;
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seq_printf(seq, "%s\n", target->name);
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return seq_has_overflowed(seq);
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if (*target->name)
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seq_printf(seq, "%s\n", target->name);
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}
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return 0;
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}
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