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scripts: kernel-doc: split typedef complex regex
The typedef regex for function prototypes are very complex. Split them into 3 separate regex and then join them using qr. Signed-off-by: Mauro Carvalho Chehab <mchehab+huawei@kernel.org> Link: https://lore.kernel.org/r/3a4af999a0d62d4ab9dfae1cdefdfcad93383356.1603792384.git.mchehab+huawei@kernel.org Signed-off-by: Jonathan Corbet <corbet@lwn.net>
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@ -1427,17 +1427,21 @@ sub dump_enum($$) {
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}
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}
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my $typedef_type = qr { ((?:\s+[\w\*]+){1,8})\s* }x;
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my $typedef_ident = qr { \*?\s*(\w\S+)\s* }x;
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my $typedef_args = qr { \s*\((.*)\); }x;
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my $typedef1 = qr { typedef$typedef_type\($typedef_ident\)$typedef_args }x;
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my $typedef2 = qr { typedef$typedef_type$typedef_ident$typedef_args }x;
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sub dump_typedef($$) {
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my $x = shift;
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my $file = shift;
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$x =~ s@/\*.*?\*/@@gos; # strip comments.
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# Parse function prototypes
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if ($x =~ /typedef((?:\s+[\w\*]+){1,8})\s*\(\*?\s*(\w\S+)\s*\)\s*\((.*)\);/ ||
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$x =~ /typedef((?:\s+[\w\*]+\s+){1,8})\s*\*?(\w\S+)\s*\s*\((.*)\);/) {
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# Function typedefs
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# Parse function typedef prototypes
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if ($x =~ $typedef1 || $x =~ $typedef2) {
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$return_type = $1;
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$declaration_name = $2;
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my $args = $3;
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