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serial: sirf: transfer more bytes once to decrease interrupts
the current codes send 1 bytes, then after getting TX done interrupt, send subsequent bytes. it causes redundant interrupts. for example, if we have 3 bytes in TX buffer, the TX flow is: 1. send 1 byte 2. get TX down interrupt 3. send the left 2 bytes 4. get TX down interrupt this patch moves to send more bytes and decrease interrupts, the new flow is: 1. send 3 bytes 2. get TX down interrupt Signed-off-by: Qipan Li <Qipan.Li@csr.com> Signed-off-by: Barry Song <Baohua.Song@csr.com> Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
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@ -290,7 +290,8 @@ static void sirfsoc_uart_start_tx(struct uart_port *port)
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if (sirfport->tx_dma_chan)
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sirfsoc_uart_tx_with_dma(sirfport);
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else {
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sirfsoc_uart_pio_tx_chars(sirfport, 1);
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sirfsoc_uart_pio_tx_chars(sirfport,
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SIRFSOC_UART_IO_TX_REASONABLE_CNT);
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wr_regl(port, ureg->sirfsoc_tx_fifo_op, SIRFUART_FIFO_START);
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if (!sirfport->is_marco)
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wr_regl(port, ureg->sirfsoc_int_en_reg,
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@ -449,4 +449,4 @@ struct sirfsoc_uart_port {
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/* I/O Mode */
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#define SIRFSOC_UART_IO_RX_MAX_CNT 256
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#define SIRFSOC_UART_IO_TX_REASONABLE_CNT 6
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#define SIRFSOC_UART_IO_TX_REASONABLE_CNT 256
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