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btrfs: make tree iteration in extent_io_tree_release() more efficient

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Currently extent_io_tree_release() is a loop that keeps getting the first
node in the io tree, using rb_first() which is a loop that gets to the
leftmost node of the rbtree, and then for each node it calls rb_erase(),
which often requires rebalancing the rbtree.

We can make this more efficient by using
rbtree_postorder_for_each_entry_safe() to free each node without having
to delete it from the rbtree and without looping to get the first node.

Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
This commit is contained in:
Filipe Manana 2023-09-22 11:39:07 +01:00 committed by David Sterba
parent df2a8e70c3
commit 63ffc1f7c4
1 changed files with 13 additions and 8 deletions
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21
fs/btrfs/extent-io-tree.c
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@ -114,14 +114,15 @@ void extent_io_tree_init(struct btrfs_fs_info *fs_info,
*/
void extent_io_tree_release(struct extent_io_tree *tree)
{
spin_lock(&tree->lock);
while (!RB_EMPTY_ROOT(&tree->state)) {
struct rb_node *node;
struct extent_state *state;
struct rb_root root;
struct extent_state *state;
struct extent_state *tmp;
node = rb_first(&tree->state);
state = rb_entry(node, struct extent_state, rb_node);
rb_erase(&state->rb_node, &tree->state);
spin_lock(&tree->lock);
root = tree->state;
tree->state = RB_ROOT;
rbtree_postorder_for_each_entry_safe(state, tmp, &root, rb_node) {
/* Clear node to keep free_extent_state() happy. */
RB_CLEAR_NODE(&state->rb_node);
ASSERT(!(state->state & EXTENT_LOCKED));
/*
@ -131,9 +132,13 @@ void extent_io_tree_release(struct extent_io_tree *tree)
*/
ASSERT(!waitqueue_active(&state->wq));
free_extent_state(state);
cond_resched_lock(&tree->lock);
}
/*
* Should still be empty even after a reschedule, no other task should
* be accessing the tree anymore.
*/
ASSERT(RB_EMPTY_ROOT(&tree->state));
spin_unlock(&tree->lock);
}