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bonding: properly unset current_arp_slave on slave link up

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When a slave comes up, we're unsetting the current_arp_slave without
removing active flags from it, which can lead to situations where we have
more than one slave with active flags in active-backup mode.

To avoid this situation we must remove the active flags from a slave before
removing it as a current_arp_slave.

Signed-off-by: Veaceslav Falico <vfalico@redhat.com>
Signed-off-by: Jay Vosburgh <fubar@us.ibm.com>
Signed-off-by: Andy Gospodarek <andy@greyhouse.net>
Signed-off-by: Marcelo Ricardo Leitner <mleitner@redhat.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
This commit is contained in:
Veaceslav Falico 2012-04-05 03:47:43 +00:00 committed by David S. Miller
parent bcf1b70ac6
commit 5a4309746c
1 changed files with 5 additions and 1 deletions
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6
drivers/net/bonding/bond_main.c
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@ -3010,7 +3010,11 @@ static void bond_ab_arp_commit(struct bonding *bond, int delta_in_ticks)
trans_start + delta_in_ticks)) ||
bond->curr_active_slave != slave) {
slave->link = BOND_LINK_UP;
bond->current_arp_slave = NULL;
if (bond->current_arp_slave) {
bond_set_slave_inactive_flags(
bond->current_arp_slave);
bond->current_arp_slave = NULL;
}
pr_info("%s: link status definitely up for interface %s.\n",
bond->dev->name, slave->dev->name);