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ACPI: Fix a hard coding style when determining if a device is a container, v3
"ACPI0004","PNP0A05" and "PNP0A06" are all defined in array container_device_ids[], so use it, but not the hard coding style. Also, introduce a new API is_container_device() to determine if a device is a container device. Signed-off-by: Tang Chen <tangchen@cn.fujitsu.com> Signed-off-by: Yasuaki Ishimatsu <isimatu.yasuaki@jp.fujitsu.com> Reviewed-by: Bjorn Helgaas <bhelgaas@google.com> Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
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@ -92,6 +92,19 @@ static int is_device_present(acpi_handle handle)
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return ((sta & ACPI_STA_DEVICE_PRESENT) == ACPI_STA_DEVICE_PRESENT);
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}
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static bool is_container_device(const char *hid)
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{
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const struct acpi_device_id *container_id;
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for (container_id = container_device_ids;
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container_id->id[0]; container_id++) {
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if (!strcmp((char *)container_id->id, hid))
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return true;
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}
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return false;
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}
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/*******************************************************************/
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static int acpi_container_add(struct acpi_device *device)
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{
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@ -232,10 +245,8 @@ container_walk_namespace_cb(acpi_handle handle,
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goto end;
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}
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if (strcmp(hid, "ACPI0004") && strcmp(hid, "PNP0A05") &&
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strcmp(hid, "PNP0A06")) {
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if (!is_container_device(hid))
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goto end;
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}
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switch (*action) {
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case INSTALL_NOTIFY_HANDLER:
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