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x86/fpu: Always allow FPU in interrupt if use_eager_fpu()
The __thread_has_fpu() check in interrupted_kernel_fpu_idle() was needed to prevent the nested kernel_fpu_begin(). Now that we have in_kernel_fpu and !__thread_has_fpu() case in __kernel_fpu_begin() does not depend on use_eager_fpu() (except clts) we can remove it. __thread_has_fpu() can be false even if use_eager_fpu(), but this case does not differ from !use_eager_fpu() case except we should not worry about X86_CR0_TS, __kernel_fpu_begin()/end() will not touch this bit. Note: I think we can kill all irq_fpu_usable() checks except in_kernel_fpu, just we need to record the state of X86_CR0_TS in __kernel_fpu_begin() and conditionalize stts() in __kernel_fpu_end(), but this needs another patch. Signed-off-by: Oleg Nesterov <oleg@redhat.com> Reviewed-by: Rik van Riel <riel@redhat.com> Acked-by: Andy Lutomirski <luto@amacapital.net> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Suresh Siddha <sbsiddha@gmail.com> Link: http://lkml.kernel.org/r/20150119185151.GC16427@redhat.com Signed-off-by: Borislav Petkov <bp@suse.de>
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@ -41,8 +41,8 @@ void kernel_fpu_enable(void)
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* be set (so that the clts/stts pair does nothing that is
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* visible in the interrupted kernel thread).
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*
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* Except for the eagerfpu case when we return 1 unless we've already
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* been eager and saved the state in kernel_fpu_begin().
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* Except for the eagerfpu case when we return true; in the likely case
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* the thread has FPU but we are not going to set/clear TS.
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*/
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static inline bool interrupted_kernel_fpu_idle(void)
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{
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@ -50,7 +50,7 @@ static inline bool interrupted_kernel_fpu_idle(void)
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return false;
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if (use_eager_fpu())
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return __thread_has_fpu(current);
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return true;
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return !__thread_has_fpu(current) &&
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(read_cr0() & X86_CR0_TS);
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