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ipv6: remove unnecessary dst_hold() in ip6_fragment()
In ipv6 tx path, rcu_read_lock() is taken so that dst won't get freed during the execution of ip6_fragment(). Hence, no need to hold dst in it. Signed-off-by: Wei Wang <weiwan@google.com> Acked-by: Martin KaFai Lau <kafai@fb.com> Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -698,8 +698,6 @@ int ip6_fragment(struct net *net, struct sock *sk, struct sk_buff *skb,
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ipv6_hdr(skb)->payload_len = htons(first_len -
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sizeof(struct ipv6hdr));
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dst_hold(&rt->dst);
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for (;;) {
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/* Prepare header of the next frame,
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* before previous one went down. */
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@ -742,7 +740,6 @@ int ip6_fragment(struct net *net, struct sock *sk, struct sk_buff *skb,
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if (err == 0) {
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IP6_INC_STATS(net, ip6_dst_idev(&rt->dst),
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IPSTATS_MIB_FRAGOKS);
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ip6_rt_put(rt);
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return 0;
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}
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@ -750,7 +747,6 @@ int ip6_fragment(struct net *net, struct sock *sk, struct sk_buff *skb,
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IP6_INC_STATS(net, ip6_dst_idev(&rt->dst),
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IPSTATS_MIB_FRAGFAILS);
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ip6_rt_put(rt);
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return err;
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slow_path_clean:
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